Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 7 - Exponents and Exponential Functions - 7-2 Scientific Notation - Practice and Problem-Solving Exercises - Page 425: 49


The solution is $3^{\frac{9}{2}}$$\times$$2^{x+y}$

Work Step by Step

The solution is $3^{\frac{9}{2}}$$\times$$2^{x+y}$ because when we multiply $3^{2}$ with $3^{\frac{1}{4}}$ you add the exponents as 1/4 plus 2 equals 2.25 which is 9/4 with base 3 which becomes $3^{\frac{9}{2}}$. Now to solve for the multiplication of $2^{x}$ and $2^{y}$, you keep the same base which is 2 and add the exponents so it becomes x+y and thus get $2^{x+y}$.
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