## Algebra 1

The solution is $3^{\frac{9}{2}}$$\times$$2^{x+y}$
The solution is $3^{\frac{9}{2}}$$\times$$2^{x+y}$ because when we multiply $3^{2}$ with $3^{\frac{1}{4}}$ you add the exponents as 1/4 plus 2 equals 2.25 which is 9/4 with base 3 which becomes $3^{\frac{9}{2}}$. Now to solve for the multiplication of $2^{x}$ and $2^{y}$, you keep the same base which is 2 and add the exponents so it becomes x+y and thus get $2^{x+y}$.