Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 7 - Exponents and Exponential Functions - 7-1 Zero and Negative Exponents - Practice and Problem-Solving Exercises - Page 417: 34


$\frac{x^2}{8 z^7}$

Work Step by Step

We start with the given expression: $2^{-3}x^2z^{-7}$ The negative exponent rule states that for every nonzero number $a$ and integer $n$, $a^{-n}=\frac{1}{a^n}$. We use this rule to rearrange the expression as follows: $\frac{x^2}{2^3z^7}$ We expand the constant exponent in the denominator: $\frac{x^2}{2\times2\times2\times z^7}=\frac{x^2}{8 z^7}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.