#### Answer

$\frac{6}{ac^3}$

#### Work Step by Step

We start with the given expression: $\frac{6a^{-1}c^{-3}}{d^0}$
The zero as an exponent rule states that for every nonzero number $a$, $a^0=1$.
We use this rule to rewrite the expression as follows: $\frac{6a^{-1}c^{-3}}{1}$
Since any number divided by $1$ is itself, we can disregard the denominator: $6a^{-1}c^{-3}$
The negative exponent rule states that for every nonzero number $a$ and integer $n$, $a^{-n}=\frac{1}{a^n}$.
We use this rule to rearrange the $a$ and $c$ terms of the expression as follows: $\frac{6}{ac^3}$