Answer
$\frac{1}{9n}$
Work Step by Step
We start with the given expression: $\frac{3^{-2}}{n}$.
The negative exponent rule states that for every nonzero number $a$ and integer $n$, $a^{-n}=\frac{1}{a^n}$.
We use the rule to rearrange the expression as follows: $\frac{1}{3^2n}$.
We expand the exponent in the denominator: $\frac{1}{3\times3n}=\frac{1}{9n}$.