## Algebra 1

Published by Prentice Hall

# Chapter 6 - Systems of Equations and Inequalities - Chapter Test - Page 407: 9

#### Answer

So our solution is: (−88/38, −29/19)

#### Work Step by Step

Our first two equations: 1. 3x+2y=-10 2. 2x-5y=3 First lets multiply the first equation by 2 and the second equation by 3. 1. 2(3x+2y=-10) 2. 3(2x-5y=3) = 1. 6x+4y=-20 2. 6x-15y=9 Now subtract the second equation from the first equation. We get: 19y=-29 (Divide by 19 on both sides) y=−29/19 Now lets plug this into the second equation to find the value of x. 2x-5(−29/19)=3 2x+145/19=3 (Subtract (145/19) from both sides of the equation) 2x=−88/19. (Divide by 2 to both sides) x=−88/38 So our solution is: (−88/38, −29/19)

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