## Algebra 1

($-\frac{88}{38}$, $-\frac{29}{19}$)
Our first two equations: 1. 3x+2y=-10 2. 2x-5y=3 First lets multiply the first equation by 2 and the second equation by 3. 1. 2(3x+2y=-10) 2. 3(2x-5y=3) = 1. 6x+4y=-20 2. 6x-15y=9 Now subtract the second equation from the first equation. We get: 19y=-29 (Divide by 19 on both sides) y=$-\frac{29}{19}$ Now lets plug this into the second equation to find the value of x. 2x-5($-\frac{29}{19}$)=3 2x+$\frac{145}{19}$=3 (Subtract (145/19) from both sides of the equation) 2x=$-\frac{88}{19}$. (Divide by 2 to both sides) x=$-\frac{88}{38}$ So our solution is: ($-\frac{88}{38}$, $-\frac{29}{19}$)