Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 6 - Systems of Equations and Inequalities - 6-2 Solving Systems Using Substitution - Practice and Problem-Solving Exercises - Page 371: 22



Work Step by Step

You change the first so the equation equals x so now you have the equations:x=2y-5 and 3x+7y=24. Now you use substitution to solve: 3(2y-1)+7y=24 6y-15+7y=24 13y-15=24 13y=39 y=3 Plug in y=3 into one of the equations: 3x+7(3)=24 3x+21=24 3x=3 x=1 So the solution is (1,3)
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