Answer
(-11,-19)
Work Step by Step
Solve the first equation for y.
$y-2x=3$ : add 2x to each side
$y-2x+2x=3+2x$
$y=3+2x$
Substitute for y in the second equation and solve for x.
$3x-2y=5$
$3x-2(3+2x)=5$
$3x-6-4x=5$
$-x-6=5$
$-x-6+6=5+6$
$-x=11$
$-x\times-1=11\times-1$
$x=-11$
Substitute -11 for x in the first equation to find y.
$y-2x=3$
$y-2(-11)=3$
$y+22=3$
$y+22-22=3-22$
$y=-19$
Check the answer by substituting the values into each equation.
$y-2x=3$
$-19-2(-11)=3$
$-19+22=3$
$3=3\checkmark$
$3x-2y=5$
$3(-11)-2(-19)=5$
$-33+38=5$
$5=5\checkmark$
