## Algebra 1

Solve the first equation for y. $y-2x=3$ : add 2x to each side $y-2x+2x=3+2x$ $y=3+2x$ Substitute for y in the second equation and solve for x. $3x-2y=5$ $3x-2(3+2x)=5$ $3x-6-4x=5$ $-x-6=5$ $-x-6+6=5+6$ $-x=11$ $-x\times-1=11\times-1$ $x=-11$ Substitute -11 for x in the first equation to find y. $y-2x=3$ $y-2(-11)=3$ $y+22=3$ $y+22-22=3-22$ $y=-19$ Check the answer by substituting the values into each equation. $y-2x=3$ $-19-2(-11)=3$ $-19+22=3$ $3=3\checkmark$ $3x-2y=5$ $3(-11)-2(-19)=5$ $-33+38=5$ $5=5\checkmark$