## Algebra 1

$( -\frac{5}{7}, \frac{16}{7})$
We know that y=x+3. Thus, in the second equation, wherever we see y, we will substitute x+3, and then we will solve: $3x+4(x+3)=7 \\\\ 7x+12 =7 \\\\ 7x=-5 \\\\ x=-\frac{5}{7}$ We now substitute x=-5/7 back in: y=(-5/7)+3=$\frac{16}{7}$ We plug our values for x and y back into the first equation and confirm that our answer is, indeed, correct.