## Algebra 1

$\frac{3}{4}$=a
When a linear equation is written in slope-intercept form, or y=mx+b form, m=slope and b=y-intercept. The equation y=$\frac{3}{4}$ax+3 is written in y=mx+b form and has a slope of $\frac{3}{4}$a Since m= $\frac{9}{16}$, we can solve for a now that we know m=$\frac{3}{4}$a because if m=$\frac{9}{16}$, and m=$\frac{3}{4}$a, then $\frac{9}{16}$=$\frac{3}{4}$a Now, to solve for a, we multiply by $\frac{4}{3}$ on both sides ($\frac{4}{3}$)$\frac{9}{16}$=($\frac{4}{3}$)$\frac{3a}{4}$ $\frac{36}{48}$=a $\frac{3}{4}$=a