## Algebra 1

To solve for n in the equation $\frac{7}{n}$=$\frac{-35}{50}$, we first cross multiply to get the equation (7)(50)=(-35)(n) 350=-35n Then, to solve for n, we'll divide by -35 on both sides of the equation $\frac{350}{-35}$=$\frac{-35n}{-35}$ y=-10