## Algebra 1

To solve for y in the equation $\frac{y}{3}$=$\frac{25}{15}$, we first cross multiply to get the equation (y)(15)=(25)(3) 15y=75 Then, to solve for n, we'll divide by 15 on both sides of the equation $\frac{15y}{15}$=$\frac{75}{15}$ y=5