Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 5 - Linear Functions - 5-1 Rate of Change and Slope - Mixed Review - Page 298: 72



Work Step by Step

To solve for y in the equation $\frac{y}{3}$=$\frac{25}{15}$, we first cross multiply to get the equation (y)(15)=(25)(3) 15y=75 Then, to solve for n, we'll divide by 15 on both sides of the equation $\frac{15y}{15}$=$\frac{75}{15}$ y=5
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