Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 5 - Linear Functions - 5-1 Rate of Change and Slope - Mixed Review - Page 298: 71



Work Step by Step

To solve for n in the equation $\frac{-4}{9}$=$\frac{n}{-45}$, we first cross multiply to get the equation (-4)(-45)=(n)(9) 180=9n Then, to solve for n, we'll divide by 9 on both sides of the equation $\frac{180}{9}$=$\frac{9n}{9}$ 20=n
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