Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 3 - Solving Inequalities - 3-7 Absolute Value Equations and Inequalities - Practice and Problem-Solving Exercises - Page 211: 35

Answer

$y\leq-11$ or $y\geq-5$
1512000563

Work Step by Step

We are given $|y+8|\geq3$ This is an absolute value inequality which could be written as: $y+8\geq3$ or $y+8\leq-3$ First solution: $y+8\leq-3$ $y+8-(8)\leq-3-(8)$ $y\leq-11$ Second solution: $y+8-(8)\geq3-8$ $y\geq-5$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.