## Algebra 1

Since we already have common denominators, we can add and simplify the numerators, combining like terms as necessary: $\frac{3n+2}{n+4} - \frac{n-6}{n+4} =\frac{(3n+2)-(n-6)}{n+4} = \frac{3n+2-n+6}{n+4}= \frac{3n-n+2+6}{n+4}= \frac{2n+8}{n+4}$ Now we can reduce the fraction by factoring out 2 from the numerator and canceling out the n+4 term: $\frac{2n+8}{n+4} = \frac{2(n+4)}{n+4} = 2$