Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 11 - Rational Expressions and Functions - 11-4 Adding and Subtracting Rational Expressions - Practice and Problem-Solving Exercises: 11

Answer

$\frac{6c-28}{2c+7}$

Work Step by Step

Since we already have common denominators, we can add and simplify the numerators, and as needed, combine like terms: $\frac{5c}{2c+7} + \frac{c-28}{2c+7} =\frac{5c+(c-28)}{5c+7} = \frac{5c+c-28}{2c+7} = \frac{6c-28}{2c+7}$
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