## Algebra 1

$\frac{6c-28}{2c+7}$
Since we already have common denominators, we can add and simplify the numerators, and as needed, combine like terms: $\frac{5c}{2c+7} + \frac{c-28}{2c+7} =\frac{5c+(c-28)}{5c+7} = \frac{5c+c-28}{2c+7} = \frac{6c-28}{2c+7}$