Algebra 1

$\frac{1}{n+2}$
Since we already have common denominators, we can add and simplify the numerators: $\frac{n}{n^2 + 4n + 4} + \frac{2}{n^2 + 4n + 4} =\frac{n+2}{n^2 + 4n + 4}$ We now need to factor the denominator to see if there are any common factors: $\frac{n+2}{n^2 + 4n + 4} = \frac{n+2}{(n+2)(n+2)}$ $(n+2)$ will cancel from the numerator and denominator: $\frac{n+2}{(n+2)(n+2)} = \frac{1}{n+2}$