Answer
$\frac{n-3}{4n+5}$
Work Step by Step
$\frac{2n^2-5n-3}{4n^2-12n-7}\div\frac{4n+5}{2n-7}$
$\frac{(2n+1)(n-3)}{(2n-7)(2n+1)}*\frac{2n-7}{4n+5}$
$\frac{n-3}{2n-7}*\frac{2n-7}{4n+5}$
$\frac{n-3}{4n+5}$
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