## Algebra 1

$\frac{40}{3a^{5}}$
To find the product you must multiply the numerators and multiply the denominators $\frac{5}{3a^{2}}\times\frac{8}{a^{3}}$ $5\times8=40$ (multiplying numerators) $3a^{2}\times a^{3}=3a^{5}$ (multiplying denominators) so the answer is $\frac{40}{3a^{5}}$