Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 11 - Rational Expressions and Functions - 11-2 Multiplying and Dividing Rational Expressions - Practice and Problem-Solving Exercises: 17

Answer

$\frac{2c(c+2)}{(c-1)}$

Work Step by Step

To multiply, we need to factor the numerator of the second expression and the denominator of the first. $\frac{4c}{2c+2}\times\frac{c^2+3c+2}{c-1}$ = $\frac{4c}{(2)(c+1)}\times\frac{(c+2)(c+1)}{c-1}$ Now we can cancel out the $c+1$ factor, as well as 2 from the first numerator and denominator of the first expression, and continue multiplying: $\frac{4c}{2(c+1)}\times\frac{(c+2)(c+1)}{c-1}$ = $\frac{(2c)}{1}\times\frac{(c+2)}{c-1}$ = $\frac{2c(c+2)}{(c-1)}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.