Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 10 - Radical Expressions and Equations - 10-3 Operations with Radial Expressions - Lesson Check - Page 616: 7

Answer

A) $\sqrt 13 - 2$ and $\sqrt 13 + 2$ B) $\sqrt 6 + 3$ and $\sqrt 6 + 3$ C) $\sqrt 5 - \sqrt 10 $ and $\sqrt 5 + \sqrt 10 $

Work Step by Step

Conjugates are the sum and difference of the same two terms A) $\sqrt 13 - 2$ has the conjugate of $\sqrt 13 + 2$ because the -2 changes to +2 in the conjugate B) $\sqrt 6 + 3$ has the conjugate of $\sqrt 6 + 3$ because the +3 changes to -3 in the conjugate C) $\sqrt 5 - \sqrt 10 $ has the conjugate of $\sqrt 5 + \sqrt 10 $ because the $-\sqrt 10$ changes to $+\sqrt 10$ in the conjugate
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.