Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 10 - Radical Expressions and Equations - 10-3 Operations with Radial Expressions - Lesson Check: 5

Answer

$3\sqrt5-\sqrt10$

Work Step by Step

$\frac{7\sqrt5}{3+\sqrt2}\longrightarrow$ multiply numerator and denominator by the conjugate of the denominator =$\frac{7\sqrt5}{3+\sqrt2}\times\frac{3-\sqrt2}{3-\sqrt2}\longrightarrow$ multiply =$\frac{7\sqrt5(3-\sqrt2)}{9-2}\longrightarrow$ use the distributive property =$\frac{21\sqrt5-7\sqrt{10}}{7}\longrightarrow$ divide by 7 =$3\sqrt5-\sqrt10$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.