Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 10 - Radical Expressions and Equations - 10-3 Operations with Radial Expressions - Lesson Check: 6

Answer

$2\sqrt7-4$

Work Step by Step

$\frac{6}{\sqrt7+2}\longrightarrow$ multiply numerator and denominator by conjugate of denominator =$\frac{6}{\sqrt7+2}\times\frac{\sqrt7-2}{\sqrt7-2}\longrightarrow$ multiply =$\frac{6\sqrt7-12}{7-4}\longrightarrow$ simplify =$\frac{6\sqrt7-12}{3}\longrightarrow$ divide by 3 =$2\sqrt7-4$
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