Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 1 - Foundations for Algebra - 1-3 Real Numbers and the Number Line - Practice and Problem-Solving Exercises: 9

Answer

$6$

Work Step by Step

According to the textbook, a number, $a$, is a square root of another number, $b$, if $a^2=b$. $6^2=36$, so $6$ is a square root of 36. Therefore: $\sqrt {36}=6$
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