Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 1 - Foundations for Algebra - 1-3 Real Numbers and the Number Line - Practice and Problem-Solving Exercises - Page 20: 10

Answer

$13$

Work Step by Step

According to the textbook, a number, $a$, is a square root of another number, $b$, if $a^2=b$. $13^2=169$, so $13$ is a square root of $169$. Therefore: $\sqrt {169}=13$
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