## Algebra 1

$5\frac{2}{3}>\sqrt {29}$
First, we write the fraction as a decimal: $5\frac{2}{3}=5+\frac{2}{3}\approx5+.667=5.667$ Next, we write the square root as a decimal: $\sqrt {29}\approx5.385$ Since $5.667$ is greater than $5.385$, we write the comparison as $5\frac{2}{3}>\sqrt {29}$