## Algebra 1: Common Core (15th Edition)

$x=0.1$ or $x=-0.3$
$64x^2+12x-1=0$ Use the quadratic formula. $x=\frac{-(12)+\sqrt (12)^2-4.(64).(-1)}{2.(64)}$ $x=\frac{-12 \pm 20}{128}$ $x=\frac{-12+20}{128}$ or $x=\frac{-12- 20}{128}$ $x=0.1$ or $x=-0.3$