Answer
$x=-\frac{3}{2}$ or $x=-2$
Work Step by Step
$2x^2+7x=-6$
$x^2+\frac{7}{2}x=-3$
$(x+\frac{7}{4})^2=\frac{1}{16}$
$x+\frac{7}{4}=\pm \frac{1}{16}$
$x+\frac{7}{4}= \frac{1}{16}$ or $x+\frac{7}{4}=- \frac{1}{16}$
$x=-\frac{3}{2}$ or $x=-2$