$x=\pm \sqrt 14 -3$
Work Step by Step
$x^2+6x-5=0$ $x^2+6x+9=14$ $(x+3)^2=14$ $x+3=\pm \sqrt 14$ $x=\pm \sqrt 14 -3$
You can help us out by revising, improving and updating this answer.Update this answer
After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.