Answer
$\pm3$
Work Step by Step
$$ \text{The quadratic formula is given by:}$$ $$ x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}$$
$$ \text{Plugging in the given values:}$$
$$a=13, b=0, c=-117$$
$$ x = \frac{-0 \pm \sqrt{0^2-4(13)(-117)}}{2(13)}$$
$$\text{Reducing within the radical gives: } $$
$$ x = \frac{-0 \pm \sqrt{6084}}{(2)13}$$
$$ \text {This gives: } $$
$$x=3,-3$$