Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 9 - Quadratic Functions and Equations - 9-6 The Quadratic Formula and the Discriminant - Practice and Problem-Solving Exercises - Page 587: 32

Answer

Two solutions

Work Step by Step

$$ \text{The quadratic formula is given by:}$$ $$ x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}$$ $$ \text{Plugging in the given values:}$$ $$a=1, b=0, c=-15$$ $$ x = \frac{-0 \pm \sqrt{0^2-4(1)(-15)}}{2(1)}$$ $$\text{Reducing within the radical gives: } $$ $$ x = \frac{-0 \pm \sqrt{60}}{(2)1}$$ $$ \text {This gives: } $$ $$x=3.87298334620742,-3.87298334620742$$
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