Answer
$$\fbox{No Solution}$$
Work Step by Step
$$ \text{The quadratic formula is given by:}$$ $$ x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}$$
$$ \text{Plugging in the given values:}$$
$$a=1, b=-2, c=3$$
$$ x = \frac{--2 \pm \sqrt{-2^2-4(1)(3)}}{2(1)}$$
$$\text{Reducing within the radical gives: } $$
$$ x = \frac{--2 \pm \sqrt{-8}}{(2)1}$$
$$\text{It is impossible to take the square root of a negative number, so there is no solution.}$$
