#### Answer

$x=-1$
$x=-\dfrac{3}{2}$

#### Work Step by Step

$x=\dfrac{-b±{\sqrt {b^{2}-4ac}}}{2a}$ and $2x^{2}+5x+3=0$.Therefore, $a=2$,$b=2$ and $c=3$:
Substitute the values:
$x=\dfrac{-5±{\sqrt {4^{2}-4(2)(3)}}}{2(2)}$
=$\dfrac{-5±{\sqrt {25-24}}}{4}$
=$\dfrac{-5±1}{4}$
Separate the equation into plus and minus equations:
$x=\dfrac{-5+1}{4}=-1$
$x=\dfrac{-5-1}{4}={\dfrac{-3}{2}}$