#### Answer

$x=-12$
$x={\dfrac{-8}{3}}$

#### Work Step by Step

$x=\dfrac{-b±{\sqrt {b^{2}-4ac}}}{2a}$ and $3x^{2}+44x+96=0$.Therefore, $a=3$,$b=44$ and $c=96$
Substitute the values:
$x=\dfrac{-44±{\sqrt {44^{2}-4(3)(96)}}}{2(3)}$
=$\dfrac{-44±{\sqrt {1936-1152}}}{6}$
=$\dfrac{-44± {\sqrt {784}}}{6}$
=$\dfrac{-44±28}{6}$
Separate the equation into plus and minus equations:
$x=\dfrac{-44-28}{6}=-12$
$x=\dfrac{-44+28}{6}={\dfrac{-8}{3}}$