Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 9 - Quadratic Functions and Equations - 9-4 Factoring to Solve Quadratic Equations - Practice and Problem-Solving Exercises - Page 571: 37


The equation has two solutions, $x=\pm k$.

Work Step by Step

We are given $x^2-k^2=0$ $(x-k)(x+k)=0$ $x-k=0$ or $x+k=0$ $x=k$ or $x=-k$ Therefore, the equation has two solutions, $x=\pm k$.
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