Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 9 - Quadratic Functions and Equations - 9-4 Factoring to Solve Quadratic Equations - Practice and Problem-Solving Exercises - Page 571: 25


$b = \pm \frac{4}{3}$

Work Step by Step

$9b^2=16$ $9b^2-16=0$ $(3b)^2-4^2=0$ $(3b-4)(3b+4)=0$ $3b-4=0$ or $3b+4=0$ $b = \pm \frac{4}{3}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.