#### Answer

$a=-2$ or $a=-6$

#### Work Step by Step

We are given:
$a^2+8a+12=0$
$a^2+2a+6a+12$
$(a+2)(a+6)=0$
$a+2$ or $a+6=0$
$a=-2$ or $a=-6$

Published by
Prentice Hall

ISBN 10:
0133281140

ISBN 13:
978-0-13328-114-9

$a=-2$ or $a=-6$

We are given:
$a^2+8a+12=0$
$a^2+2a+6a+12$
$(a+2)(a+6)=0$
$a+2$ or $a+6=0$
$a=-2$ or $a=-6$

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