Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 9 - Quadratic Functions and Equations - 9-4 Factoring to Solve Quadratic Equations - Practice and Problem-Solving Exercises - Page 571: 30


$a=-2$ or $a=-6$

Work Step by Step

We are given: $a^2+8a+12=0$ $a^2+2a+6a+12$ $(a+2)(a+6)=0$ $a+2$ or $a+6=0$ $a=-2$ or $a=-6$
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