Answer
$4b^{2}-33b+8$
Work Step by Step
$(4b-1)(b-8)=$
$...$distribute the second factor, $(b-8)$.
$=4b(b-8)-1(b-8)$
...distribute $4b$.
$=4b^{2}-32b-1(b-8)$
...distribute $-1$.
$=4b^{2}-32b-b+8$
...gather like terms.
=$4b^{2}-33b+8$
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 8 - Polynomials and Factoring - Mid-Chapter Quiz - Page 510: 14
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