## Algebra 1: Common Core (15th Edition)

$11(7x^{3}+2x^{2}-3x-8)$
List factors of each term. Note the common factors. $77x^{3}=7\cdot(11)\cdot x\cdot x\cdot x$ $22x^{2}=2\cdot(11)\cdot x\cdot x$ $33x=3\cdot(11)\cdot x$ $88=2\cdot 2\cdot 2\cdot(11)$ GCF=$11$. $77x^{3}+22x^{2}-33x-88$ = ...factor out the GCF from each term. $=11(7x^{3})+11(2x^{2})-11(3x)-11(8)$ ...apply the Distributive Property. =$11(7x^{3}+2x^{2}-3x-8)$