## Algebra 1: Common Core (15th Edition)

No, because $(3+\displaystyle \frac{1}{2})^{2}\neq 9\frac{1}{4}$
No, because $3\displaystyle \frac{1}{2}=3+\frac{1}{2}$, so we square the binomial: $(3+\displaystyle \frac{1}{2})^{2}=3^{2}+2(3)(\frac{1}{2})+(\frac{1}{2})^{2}=$ $=9+3+\displaystyle \frac{1}{4}$ $=12\displaystyle \frac{1}{4}\neq 9\frac{1}{4}$