Answer
No, because $(3+\displaystyle \frac{1}{2})^{2}\neq 9\frac{1}{4}$
Work Step by Step
No, because
$3\displaystyle \frac{1}{2}=3+\frac{1}{2}$, so
we square the binomial:
$(3+\displaystyle \frac{1}{2})^{2}=3^{2}+2(3)(\frac{1}{2})+(\frac{1}{2})^{2}=$
$=9+3+\displaystyle \frac{1}{4}$
$=12\displaystyle \frac{1}{4}\neq 9\frac{1}{4}$
