Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 8 - Polynomials and Factoring - 8-4 Multiplying Soecial Cases - Practice and Problem-Solving Exercises - Page 508: 55


No, because $(3+\displaystyle \frac{1}{2})^{2}\neq 9\frac{1}{4}$

Work Step by Step

No, because $3\displaystyle \frac{1}{2}=3+\frac{1}{2}$, so we square the binomial: $(3+\displaystyle \frac{1}{2})^{2}=3^{2}+2(3)(\frac{1}{2})+(\frac{1}{2})^{2}=$ $=9+3+\displaystyle \frac{1}{4}$ $=12\displaystyle \frac{1}{4}\neq 9\frac{1}{4}$
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