Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 8 - Polynomials and Factoring - 8-4 Multiplying Soecial Cases - Practice and Problem-Solving Exercises - Page 508: 48



Work Step by Step

$(2p^{2}+7q)(2p^{2}+7q)$ ...identify which terms correspond to $a $ and $b $ in the rule for the product of a sum and difference ($(a+b)(a-b)=a^{2}-b^{2}$). $a=2p^{2},\ b=7q$ ...substitute for $a $and $b $ in the rule $(2p^{2}+7q)(2p^{2}+7q)=(2p^{2})^{2}-(7q)^{2}$ ...simplify. =$4p^{4}-49q^{2}$
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