Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 8 - Polynomials and Factoring - 8-4 Multiplying Soecial Cases - Practice and Problem-Solving Exercises - Page 508: 36

Answer

$m^{2}$+6mn+9$n^{2}$

Work Step by Step

There is one formula you can use in this case: $(a+b)^{2}$=$a^{2}$+2ab+$b^{2}$ => $(m+3n)^{2}$ =$m^{2}$+2(m)(3n)+$(3n)^{2}$ (Apply the formula above) =$m^{2}$+6mn+9$n^{2}$ (Now, simplify)
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