Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 7 - Exponents and Exponential Functions - Chapter Test - Page 479: 1



Work Step by Step

You have $\frac{r^3t^-7}{t^1{^2}}$.You have to simplify it: $\frac{r^3t^-7}{t^1{^2}}$ -apply exponent rule $\frac{x^a}{x^b}$=$\frac{1}{x^b{^-a}}$- $\frac{t^-{^7}}{t^5}$=$\frac{1}{t^5{^-}{^(}{^-}{^7}{^)}}$=$\frac{1}{t^1{^2}}$ The simplified expression is $\frac{r^3}{t^1{^2}}$
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