Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 7 - Exponents and Exponential Functions - Chapter Test - Page 479: 18

Answer

(-2,8)(0,2)(2,$\frac{1}{2}$)

Work Step by Step

You have y= 2 $\times$ ($\frac{1}{2}$$)^{x}$. Plug in the values x=-2,0,2 to find the y-value. X=-2 y=2 $\times$ ($\frac{1}{2}$$)^{-2}$ y=2 $\times$ 4 y=8 x=0 y= 2 $\times$ ($\frac{1}{2}$$)^{0}$ -any number raised to 0 always equals 1- y=2 $\times$ 1 y=2 x=2 y= 2 $\times$ ($\frac{1}{2}$$)^{2}$ y=2 $\times$ $\frac{1}{4}$ y=$\frac{1}{2}$
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