Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 7 - Exponents and Exponential Functions - Chapter Test - Page 479: 17

Answer

(-2,$\frac{1}{8}$)(0,$\frac{1}{2}$)(2,2)
1531261005

Work Step by Step

You have y=$\frac{1}{2}$ $\times$ $2^{x}$.Plug in the values x=-2,0,2 to find the y-value. X=-2 y=$\frac{1}{2}$ $\times$ $2^{-2}$ y=$\frac{1}{2}$ $\times$ $\frac{1}{4}$ y=$\frac{1}{8}$ x=0 y=$\frac{1}{2}$ $\times$ $2^{0}$ -any number raised to 0 always equals 1- y=$\frac{1}{2}$ $\times$ 1 y=$\frac{1}{2}$ x=2 y=$\frac{1}{2}$ $\times$ $2^{2}$ y=$\frac{1}{2}$ $\times$ 4 y=2
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.