Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 7 - Exponents and Exponential Functions - Chapter Review - Page 477: 67

Answer

f(-2)=0.16,f(0)=1,f(2)=6.25
1531252256

Work Step by Step

You have f(x)=$2.5^{x}$.Plug in x=-2,x=0,x=2 to find the y-values: x=-2: f(-2)=$2.5^{-2}$ f(-2)=0.16 x=0: f(0)=$2.5^{0}$ -any number raised to 0 always equals 1- f(0)=1 x=2: f(2)=$2.5^{2}$ f(2)=6.25 You have f(-2)=0.16,f(0)=1,f(2)=6.25.Plot the pairs and connect them to make a graph.
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