Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 7 - Exponents and Exponential Functions - Chapter Review - Page 477: 60



Work Step by Step

You have $\sqrt[3] x^6y^9$.Simplify the expression: $\sqrt[3] x^6$ $\sqrt[3] y^9$ -apply the radical rule that $\sqrt[n] ab$=$\sqrt[n] a$ $\sqrt[n] b$- $x^{6/3}$ $x^{9/3}$ -apply radical rule: $\sqrt[n] a^m$=$a^{m/n}$- =$x^{2}$$y{3}$
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