Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 7 - Exponents and Exponential Functions - Chapter Review - Page 477: 62


$x^{2/5}$ $y^{3/5}$

Work Step by Step

You have $\sqrt[5] x^2y^3$.Simplify the expression: $\sqrt[5] x^2$ $\sqrt[5] y^3$ -apply the radical rule that $\sqrt[n] ab$=$\sqrt[n] a$ $\sqrt[n] b$- $x^{2/5}$ $y^{3/5}$ -apply radical rule: $\sqrt[n] a^m$=$a^{m/n}$- =$x^{2/5}$$Y^{3/5}$
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