Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 7 - Exponents and Exponential Functions - 7-5 Rational Exponents and Radicals - Practice and Problem-Solving Exercises - Page 452: 65

Answer

$9t^{\frac{2}{3}}$

Work Step by Step

We are given: $((27t)^{\frac{1}{3}})^2$ $=((3^3t)^{\frac{1}{3}})^2$ $=((3t^{\frac{1}{3}})^2$ $=9t^{\frac{2}{3}}$
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