Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 7 - Exponents and Exponential Functions - 7-5 Rational Exponents and Radicals - Practice and Problem-Solving Exercises - Page 452: 57



Work Step by Step

We are given: $\sqrt 9s^3 + \sqrt 16s^3$ $=\sqrt 3^2s^3 + \sqrt 4^2s^3$ $=3\sqrt s^3 + 4\sqrt s^3$ $=7\sqrt s^3$ $=7s^{\frac{3}{2}}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.